미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 솔루션 Up

미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 솔루션 Up

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미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 솔루션

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1 FUNCTIONS AND MODELS
2 LIMITS AND DERIVATIVES
3 DIFFERENTIATION RULES
4 APPLICATIONS OF DIFFERENTIATION
5 INTEGRALS
6 APPLICATIONS OF INTEGRATION
7 TECHNIQUES OF INTEGRATION
8 FURTHER APPLICATIONS OF INTEGRATION
9 DIFFERENTIAL EQUATIONS
10 PARAMETRIC EQUATIONS AND POLAR COORDINATES
11 INFINITE SEQUENCES AND SERIES
12 VECTORS AND THE GEOMETRY OF SPACE
13 VECTOR FUNCTIONS
14 PARTIAL DERIVATIVES
15 MULTIPLE INTEGRALS
16 VECTOR CALCULUS
17 SECOND-ORDER DIFFERENTIAL EQUATIONS1

FUNCTIONS AND MODELS
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1.1 Four Ways to Represent a Function

In exercises requiring estimations or approximations, your answers may vary slightly from the answers given here. 1. (a) The point (?1, ?2) is on the graph of f , so f (?1) = ?2.

(b) When x = 2, y is about 2.8, so f (2) ? 2.8. (c) f (x) = 2 is equivalent to y = 2. When y = 2, we have x = ?3 and x = 1. (d) Reasonable estimates for x when y = 0 are x = ?2.5 and x = 0.3. (e) The domain of f consists of all x-values on the graph of f . For this function, the domain is ?3 ≤ x ≤ 3, or [?3, 3]. The range of f consists of all y-values on the graph of f . For this function, the range is ?2 ≤ y ≤ 3, or [?2, 3]. (f ) As x increases from ?1 to 3, y increases from ?2 to 3. Thus, f is increasing on the interval [?1, 3].
3. From Figure 1 in the text, the lowest point occurs at about (t, a) = (12, ?85). The highest point occurs at about (17, 115).

Thus, the range of the vertical gro

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자료제목 : 미분적분학 미적분학 (Calculus) 6E Solution JAMES STEWART 솔루션
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